Quack AI Announcement Telegram Channel
Quack AI Announcement (@quackaiann) is a public Telegram channel with 202,294 subscribers. It lost 1,866 subscribers in the last 7 days. Its posts average 1,528 views. It is listed under Finance and posts in English.
Reach score
In October 2026, @quackaiann reached 0.76% of its 202,294 subscribers per post (1,528 average views), placing it in the bottom quarter of tracked channels its size. The benchmark is 8,567 tracked channels with 100K-500K subscribers, whose median reach is 6.4%.
- Views per subscriber
- 0.76%
- Percentile for its size
- 10/ 100
- Views per post
- 1,528
- Band median
- 6.4%
Fewer subscribers see each post than at most channels this size. Worth asking why before you pay for the audience.
Measured against 8,567 tracked channels with 100K-500K subscribers. Views per subscriber falls as a channel grows, so @quackaiann is only ever compared with channels of its own size.
Subscriber growth
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About
Building Q402. The first unified sign-to-pay and governance layer for the Agent Economy. X: https://x.com/QuackAI_AI Linktree: https://linktr.ee/quack_ai Chat: https://t.me/quackai_Community App: https://app.quackai.ai/quackipedia
Quack AI Announcement on Telegram - frequently asked questions
- How many subscribers does Quack AI Announcement have on Telegram?
- Quack AI Announcement (@quackaiann) has 202,294 subscribers on Telegram. It lost 1,866 subscribers in the last 7 days. The count is refreshed from Telegram's public data and the growth chart above shows its history.
- How many people see Quack AI Announcement's posts?
- Each post on Quack AI Announcement (@quackaiann) averages 1,528 views against 202,294 subscribers. 0.76% of them see each post, below average for a channel its size. The comparison is 8,567 tracked channels with 100K-500K subscribers.
- How do I join Quack AI Announcement on Telegram?
- Open t.me/quackaiann in the Telegram app, or use the Open in Telegram button at the top of this page. It is a public Telegram channel, so anyone with the link can join.