EnglishShakeela Ebrahimkhil is on Twitter (X) as @shakeela3, with 56,585 followers and 1,520 posts. It has been on X since August 2011, an account age of 15 years.
Followers
57K
Growth (7d)
-
Following
383
Influence
25
Posts
1.5K~0.3/day
Likes given
288
Media posts
604
Follower ratio
148:1
Follower growth
Not enough history yet - growth is tracked from first discovery.
Buy or sell Twitter (X) accounts - escrow-protected
PlayerSells is an escrow marketplace for Twitter (X) accounts. Every deal is protected, with no middleman risk.
Check @shakeela3 with free tools
The same checks work on any X (Twitter) account. Free, no sign-up and no email.
Shadowban Checkerwhether an account is being suppressed in search and repliesFake Follower Audithow much of a follower base is realGrowth Simulatorwhere a posting habit lands an account in a yearBio Optimizerwhether a bio converts a profile visit into a followProfile Reviewan unsparing read of a profile, written by a modelX Trendswhat is trending right now, by country
Creator Rank, our free Chrome extension, shows this account's audience rank and Creator Score next to its name on X itself.
Bio
Journalist Deutsche Welle (DW) Former TOLO & TOLOnews' Journalist. All views are my own
Notable followers
The biggest accounts in our directory following @shakeela3.
Shakeela Ebrahimkhil on Twitter (X) - frequently asked questions
- What is the Twitter handle for Shakeela Ebrahimkhil?
- Shakeela Ebrahimkhil posts on Twitter (X) as @shakeela3. The profile is at x.com/shakeela3, and the View on X button at the top of this page opens it.
- How many followers does Shakeela Ebrahimkhil have on Twitter?
- Shakeela Ebrahimkhil (@shakeela3) has 56,585 followers on Twitter (X). The count is refreshed continuously from public data.
- When did Shakeela Ebrahimkhil join Twitter?
- Shakeela Ebrahimkhil joined Twitter (X) in August 2011. The @shakeela3 account is 15 years old. Searches for Shakeela Ebrahimkhil age often mean a personal age, which we do not publish. The figure here is the account age only.